2. Consider the triangle ABC and I, it's incenter . D is the other point of intersection of the line AI with the circumcircle of ABC. E and F are the feet of the altitudes drawn from I on BD and CD respectively. If IE + IF = AD/2, find the angle BAC. 5. In the triangle ABC, we know that BC > CA > AB . D is a point on BC, and E is a point on the extension of AB (near A) such that BD = BE = AC . The circumcircle of BED intersects AC at P . BP intersects the circumcircle of ABC at Q . Prove that : AQ + CQ = BP
danarCeni amocanebi gaugebrad ideba forumze, magram isini SegiZliat naxoT : http://www.geocities.com/CollegePark/Lounge/5284/math/
